Area
Interactive curriculum lessons, worked examples, and geometric problem-solving techniques designed to help Kenyan students master CBC, KPSEA, KCSE, and IGCSE mathematics.
First Principles
Objective: Calculate the total surface area of composite shapes made by joining or cutting out rectangles, triangles, circles, and semicircles.
Interactive Composite Area Explorer
Choose a shape type and adjust dimensions to see how areas decompose!
(a) Concrete Scenario: A school in Eldoret is constructing a sports field shaped like a standard stadium running track—a central rectangular football pitch bounded by two semicircular curves. To calculate the total cost of planting Kikuyu grass, the groundskeeper breaks the shape down into standard geometric regions.
(b) Geometric Insight: Any complex 2D region can be analyzed by either additive composition (adding simple component areas together) or subtractive composition (subtracting circular cut-outs or holes from a outer boundary region).
(c) Algebraic Rule: For additive composite shapes: \[A_{\text{total}} = A_{\text{rectangle}} + A_{\text{semicircle}} = (l \times w) + \frac{1}{2}\pi r^2\] For subtractive composite shapes: \[A_{\text{remaining}} = A_{\text{outer}} - A_{\text{hole}} = (l \times w) - \pi r^2\]
Key Formulas
Worked Examples
- Identify component shapes: One rectangle (\(20\text{ cm} \times 14\text{ cm}\)) and one semicircle with diameter \(d = 14\text{ cm}\) (hence radius \(r = 7\text{ cm}\)).
- Calculate rectangle area: \(A_{\text{rect}} = 20 \times 14 = 280\text{ cm}^2\).
- Calculate semicircle area: \(A_{\text{semi}} = \frac{1}{2} \times \frac{22}{7} \times 7^2 = \frac{1}{2} \times \frac{22}{7} \times 49 = 77\text{ cm}^2\).
- Combine areas: \(A_{\text{total}} = 280 + 77 = 357\text{ cm}^2\).
- Answer: \(357\text{ cm}^2\).
- Identify components: Subtractive composition — Outer rectangle minus inner circle.
- Calculate rectangle area: \(A_{\text{rect}} = 30 \times 20 = 600\text{ cm}^2\).
- Calculate circular hole area: \(A_{\text{circle}} = \frac{22}{7} \times 7^2 = 154\text{ cm}^2\).
- Subtract hole area: \(A_{\text{remaining}} = 600 - 154 = 446\text{ cm}^2\).
- Answer: \(446\text{ cm}^2\).
- Identify components: Central rectangle plus two semicircles of radius \(r = \frac{56}{2} = 28\text{ m}\). Note that two semicircles equal one full circle!
- Calculate rectangle area: \(A_{\text{rect}} = 100 \times 56 = 5,600\text{ m}^2\).
- Calculate combined curved area (1 full circle): \(A_{\text{circle}} = \frac{22}{7} \times 28^2 = \frac{22}{7} \times 784 = 2,464\text{ m}^2\).
- Total field area: \(A_{\text{total}} = 5,600 + 2,464 = 8,064\text{ m}^2\).
- Answer: \(8,064\text{ m}^2\).
Common Mistakes
Real World
Practice