Rates, Ratio, Proportions and Percentages
Interactive curriculum lessons, worked examples, and geometric problem-solving techniques designed to help Kenyan students master CBC, KPSEA, KCSE, and IGCSE mathematics.
First Principles
Core Objective: Master the interconnected mathematical language of rates, ratios, proportions, and percentages to solve real-life scaling and comparative problems.
Interactive Scaler: The Master Recipe & Proportion Lab
Adjust the servings slider below. Notice how every ingredient scales by the exact same multiplier (the scale factor), while the percentage share of each ingredient remains perfectly constant!
(a) Concrete Scenario: The Village Feast
When cooking chapati for a family of 4, you use 500 g of flour and 250 ml of water. When hosting a party for 30 guests, adding just more flour without water will ruin the dough! You must scale every ingredient by the exact same factor: \(\frac{30}{4} = 7.5\). This preservation of proportion is the foundation of proportional reasoning.
(b) Geometric & Relational Insight
A ratio compares two quantities of the same kind (e.g. 500 g flour to 250 ml water, or \(2:1\)). A proportion states that two ratios are equal: \(\frac{a}{b} = \frac{c}{d}\). Geometrically, this means scaling preserves shape and texture, stretching all dimensions uniformly.
(c) The Unified Algebraic Model
Rates, ratios, proportions, and percentages are all aspects of the same concept:
- Ratio: Dimensionless comparison \(a:b\) or \(\frac{a}{b}\).
- Rate: Comparison between two different physical units (e.g., speed = \(\frac{\text{km}}{\text{h}}\), water flow = \(\frac{\text{litres}}{\text{minute}}\)).
- Percentage: A standardized ratio with a denominator of 100: \(\frac{P}{100} = \frac{\text{Part}}{\text{Whole}}\).
- Cross-Multiplication: Whenever \(\frac{a}{b} = \frac{c}{d}\), the fundamental truth is \(a \times d = b \times c\).
Master Key: To check if two ratios are proportional, cross-multiply. If the products are equal, the ratios are directly proportional!
Key Formulas
Direct comparison of two quantities in identical units. Always simplify to simplest terms by dividing by the GCD.
Comparison of quantities with different units (e.g., \(\text{Speed} = \frac{\text{Distance}}{\text{Time}}\), \(\text{Unit Price} = \frac{\text{Cost}}{\text{Items}}\)).
The fundamental law of proportions (cross-multiplication) used to solve for an unknown value.
Standard percentage relationship between part, whole, and rate per hundred.
Measures percentage increase (positive) or percentage discount/loss (negative) always relative to the original base.
Find the value of a single unit first, then multiply by the desired target quantity.
Worked Examples
Edwin's school requires a \(20\%\) deposit before booking a tour to Nairobi National Park that costs KES 2,500 per learner. How much is the deposit?
- Identify the formula: \(\text{Part} = \frac{P}{100} \times \text{Whole}\).
- Substitute values: \(\text{Deposit} = \frac{20}{100} \times 2500\).
- Simplify: \(\frac{1}{5} \times 2500 = 500\).
A solar water pump in Isiolo fills a community tank at a steady rate of \(30\text{ litres per minute}\). How many minutes will it take to completely fill a tank with a capacity of \(1,800\text{ litres}\)?
- Identify the relationship: \(\text{Rate} = \frac{\text{Volume}}{\text{Time}} \implies \text{Time} = \frac{\text{Volume}}{\text{Rate}}\).
- Substitute values: \(\text{Time} = \frac{1800\text{ L}}{30\text{ L/min}}\).
- Calculate: \(\text{Time} = 60\text{ minutes} = 1\text{ hour}\).
A boutique importer in Mombasa orders solar lanterns costing £1,250. An international courier charges a shipping fee of \(7.5\%\) on top of the goods' cost. Calculate the total expenditure in pounds (£) including shipping.
- Method 1 (Two-step):
Find shipping fee: \(\text{Fee} = \frac{7.5}{100} \times 1250 = 0.075 \times 1250 = 93.75\).
Add to original cost: \(\text{Total} = 1250 + 93.75 = 1343.75\). - Method 2 (Multiplier method):
Total percent = \(100\% + 7.5\% = 107.5\%\).
\(\text{Total} = 1.075 \times 1250 = 1343.75\).
Common Mistakes
Example: Tripling a recipe by multiplying flour by 3, but keeping salt and water the same.
Example: An item rises from KES 100 to KES 120. A learner calculates \(\frac{20}{120} = 16.7\%\) instead of \(\frac{20}{100} = 20\%\).
Example: Writing \(\frac{\text{Distance}}{\text{Time}} = \frac{\text{Time}}{\text{Distance}}\).
Real World
Practice