Data Presentation and Interpretation
Interactive curriculum lessons, worked examples, and geometric problem-solving techniques designed to help Kenyan students master CBC, KPSEA, KCSE, and IGCSE mathematics.
First Principles
Objective: Organize raw data into frequency tables, construct and interpret charts, and calculate the mean, median, mode, and range.
Interactive Data & Averages Explorer
Add values or pick a sample dataset to watch the summary statistics & chart update!
(a) Concrete Scenario: A dairy farmer in Kiambu tracks daily milk production in liters over one week: \(12, 15, 12, 18, 10, 14, 12\). Raw numbers can look confusing in a list. Organizing them into a frequency table or bar chart makes patterns instantly visible.
(b) Central Tendency & Spread:
- Mean (\(\bar{x}\)): The equal balance point. Add all values and divide by the total number of entries \(n\).
- Median: The exact middle value when data is sorted in ascending order.
- Mode: The most frequently occurring score. Useful for inventory (e.g., most popular shoe size).
- Range: The difference between the highest and lowest values (\(\text{Max} - \text{Min}\)), indicating spread.
(c) Sector Angle in Pie Charts: When representing frequency \(f\) out of total sample \(n\) on a pie chart: \[\text{Sector Angle } (\theta) = \frac{f}{n} \times 360^\circ\]
Key Formulas
Worked Examples
- Sum of scores: \(\sum x = 14 + 18 + 12 + 16 + 20 = 80\).
- Count: \(n = 5\).
- Mean: \(\bar{x} = \frac{80}{5} = 16\).
- Range: \(\text{Max} - \text{Min} = 20 - 12 = 8\).
- Answer: Mean = 16 ; Range = 8.
\(\begin{array}{|c|c|c|} \hline \text{Shoe Size } (x) & \text{Frequency } (f) & f \cdot x \\ \hline 38 & 3 & 114 \\ 39 & 5 & 195 \\ 40 & 8 & 320 \\ 41 & 4 & 164 \\ \hline \text{Total} & \sum f = 20 & \sum f \cdot x = 793 \\ \hline \end{array}\)
- Calculate \(\sum f\): \(3 + 5 + 8 + 4 = 20\).
- Calculate \(\sum (f \cdot x)\): \(114 + 195 + 320 + 164 = 793\).
- Calculate Mean: \(\bar{x} = \frac{793}{20} = 39.65\).
- Answer: Mean shoe size = 39.65.
- Set up proportion formula: \(\theta = \frac{f}{n} \times 360^\circ\).
- Substitute known values: \(108^\circ = \frac{f}{180} \times 360^\circ\).
- Simplify: Since \(\frac{360}{180} = 2\), we have \(108 = 2f\).
- Solve for \(f\): \(f = \frac{108}{2} = 54\).
- Answer: 54 students voted for Mutua.
Common Mistakes
Real World
Practice