MathMastery.Beta
Learning Resources

Linear Inequalities

Interactive curriculum lessons, worked examples, and geometric problem-solving techniques designed to help Kenyan students master CBC, KPSEA, KCSE, and IGCSE mathematics.

Grade 09 Pathway: N/A

First Principles

Objective

Understand, solve, and graphically represent linear inequalities in one and two variables using concrete balances, number lines, and coordinate half-planes.

Interactive Visualizer: Linear Inequalities & Half-Planes

Shaded region represents all coordinate points \((x, y)\) satisfying the inequality.

(a) Concrete Scenario

Consider shopping at a local market stall. If you have a maximum of Ksh 200 in your pocket and each mango costs Ksh 40, the number of mangoes \(m\) you can purchase must satisfy:

\[ 40m \le 200 \]

Unlike an equation which gives a single exact number (\(m = 5\)), an inequality describes a full range of possibilities: \(m = 0, 1, 2, 3, 4,\) or \(5\) mangoes.

(b) Geometric Representation

  • One Variable (Number Line): A linear inequality represents a continuous ray. We place a circle at the boundary point and shade in the direction of valid values.
  • Two Variables (Cartesian Plane): An inequality such as \(y \le 2x + 1\) divides the coordinate plane into two halves separated by the boundary line \(y = 2x + 1\). All coordinate pairs \((x, y)\) on one side satisfy the inequality, creating a shaded half-plane.

(c) Algebraic Rule: The Negative Inversion

Solving linear inequalities follows the same inverse-operation steps as linear equations with one crucial distinction: multiplying or dividing both sides by a negative number reverses the inequality symbol.

Why Does the Sign Flip?

Consider the true statement \(2 < 5\). If we multiply both sides by \(-1\), we get \(-2\) and \(-5\). On the number line, \(-2\) is to the right of \(-5\), which means \(-2 > -5\). The order of values flips when reflected across zero!

Key Formulas

1. Basic Inequality Rules

\[ ax \le b \implies x \le \frac{b}{a} \quad \text{(when } a > 0\text{)} \]\[ -ax \le b \implies x \ge -\frac{b}{a} \quad \text{(when dividing by a negative number)} \]

2. Two-Step Linear Inequalities

\[ ax + b > c \implies ax > c - b \implies x > \frac{c - b}{a} \quad (a > 0) \]

3. Boundary Lines & Symbols

SymbolMeaningNumber Line2D Graph Line
\(<, >\)Strictly less / greater thanOpen circle \(\circ\)Dashed line (\(---\))
\(\le, \ge\)Less/greater than or equal toSolid dot \(\bullet\)Solid line (\(\bf{\text{---}}\))

4. Half-Plane Shading Test

For \(y < mx + c\) or \(Ax + By \le C\), test the point \((0,0)\):

  • If \((0,0)\) produces a true statement, shade the half-plane containing \((0,0)\).
  • If \((0,0)\) produces a false statement, shade the opposite half-plane.

Worked Examples

Example 1 (Easy): Solving a Two-Step Linear Inequality

Solve the inequality \(3x - 5 < 7\) and express the solution set.

  1. Isolate the variable term: Add 5 to both sides:\[ 3x < 7 + 5 \implies 3x < 12 \]
  2. Divide by the coefficient: Divide both sides by 3 (positive, so keep sign):\[ x < 4 \]
  3. Graphical representation: Open circle at \(x = 4\), shade the ray going to the left towards \(-\infty\).

Example 2 (Medium): Inequality Involving Negative Division

Solve and graph the inequality: \(-2(x + 4) \ge 10\).

  1. Expand the bracket:\[ -2x - 8 \ge 10 \]
  2. Add 8 to both sides:\[ -2x \ge 18 \]
  3. Divide by \(-2\) and reverse the inequality sign:\[ x \le \frac{18}{-2} \implies x \le -9 \]
  4. Graphical representation: Solid closed dot at \(-9\) with arrow extending to the left.

Example 3 (Hard): Graphing a Linear Inequality in Two Variables

Determine the shaded region for the inequality \(2x + 3y < 6\) on the Cartesian plane.

  1. Find intercepts for the boundary line \(2x + 3y = 6\):
    • When \(x = 0\): \(3y = 6 \implies y = 2\) → point \((0, 2)\)
    • When \(y = 0\): \(2x = 6 \implies x = 3\) → point \((3, 0)\)
  2. Draw the boundary line: Since the inequality is strict (\(<\)), connect \((0,2)\) and \((3,0)\) with a dashed line.
  3. Perform the Test Point Test using \((0,0)\):\[ 2(0) + 3(0) = 0 < 6 \quad \text{(True)} \]
  4. Shade the correct region: Since \((0,0)\) satisfies the inequality, shade the entire region below/left of the line containing the origin.

Common Mistakes

Misconception 1: Forgetting to Flip the Sign on Negative Division

The Error: Solving \(-3x \le 12\) as \(x \le -4\).
Correction: Dividing or multiplying by a negative number reverses the relational order. \(-3x \le 12 \implies x \ge -4\).
Why it feels right: Standard algebra equation solving does not require any sign inversion, so students apply equation habits without thinking.

Misconception 2: Using Solid vs. Dashed Lines Incorrectly

The Error: Drawing a solid line for \(y > 3x - 1\).
Correction: Strict inequalities (\(<\) and \(>\)) do NOT include the boundary line itself, so the line must be dashed. Inclusive inequalities (\(\le\) and \(\ge\)) use solid lines.
Why it feels right: Learners naturally draw solid axes and lines in coordinate geometry and forget that the line style carries mathematical meaning.

Misconception 3: Guessing the Shading Direction Without a Test Point

The Error: Assuming that "greater than" always means shading directly "to the right" or "above" regardless of whether \(y\) or \(x\) has a negative coefficient.
Correction: In \(-2y > 4x - 6\), dividing by \(-2\) gives \(y < -2x + 3\), meaning the solution is below the line. Always substitute \((0,0)\) into the original inequality to check.

Real World

Constraint Boundary: If she loads no beans (\(b = 0\)), she can transport up to \(m = \frac{1200}{50} = 24\) bags of maize.
Trade-offs: If she loads 10 bags of beans (\(900\text{ kg}\)), the remaining capacity allows \(50m \le 300 \implies m \le 6\) bags of maize.
Feasible Region: The shaded half-plane on the grid represents all possible cargo configurations that will not overload the vehicle.

Practice

Jackson runs a fruit stall at the local duka. Each mango costs 150 shillings. He has at most 3000 shillings to spend on mangoes today. What is the greatest number of mangoes he can buy? (Type only the number, e.g., 42)
Review the concepts above.
A shopkeeper in a duka wants his daily profit P, given by P = 5x - 150 (where x is the number of items sold), to be at least 200 shillings. What is the minimum number of items he must sell each day? (Type only the number, e.g., 45)
Review the concepts above.
A lorry can carry at most 2,500 kg of produce. Each crate weighs 4 kg plus an extra 120 kg for packaging, so the total weight is 4x + 120 kg where x is the number of crates. What is the greatest integer number of crates the lorry can carry? (Type only the number, e.g., 432)
Review the concepts above.
A matatu driver charges a fixed fare plus a per‑kilometre charge. The total fare (in shillings) for a trip of x kilometres is given by 5x - 20. The driver wants the fare to be at most 2x + 10. Find the greatest integer value of x that satisfies this condition. (Type only the number, e.g., 42)
Review the concepts above.
A matatu driver earns a fixed amount of 1500 shillings each day plus an additional 200 shillings for every passenger he transports. He wants to earn at least 8000 shillings in a day. What is the minimum whole number of passengers he must transport to meet his target? (Type only the number, e.g., 42)
Review the concepts above.
A shopkeeper sells oranges at Ksh 30 each. He wants to earn at least Ksh 4,500 from orange sales. After already selling 80 oranges, how many more oranges must he sell to reach his target? (Type only the number, e.g., 42)
Review the concepts above.