Trigonometry
Interactive curriculum lessons, worked examples, and geometric problem-solving techniques designed to help Kenyan students master CBC, KPSEA, KCSE, and IGCSE mathematics.
First Principles
Objective: Master the basic trigonometric ratios (Sine, Cosine, Tangent) to solve for unknown side lengths and angles in right-angled triangles.
Interactive SOH CAH TOA Explorer
Adjust the angle (\(\theta\)) or hypotenuse length to see how opposite and adjacent sides scale!
(a) Concrete Scenario: Imagine positioning a ladder against a wall or building a wheelchair ramp in Nakuru. The angle of elevation \(\theta\) determines how steep the incline is. Trigonometry lets us calculate how high the ladder reaches or how long the ramp must be without physically measuring them on site.
(b) Defining the Sides: In a right-angled triangle relative to acute angle \(\theta\):
- Hypotenuse (H): Longest side, always directly opposite the \(90^\circ\) right angle.
- Opposite (O): The leg directly across from angle \(\theta\).
- Adjacent (A): The leg alongside angle \(\theta\) (excluding the hypotenuse).
(c) SOH CAH TOA Memory Tool: \[\sin \theta = \frac{\text{Opposite}}{\text{Hypotenuse}} \quad (\text{SOH})\] \[\cos \theta = \frac{\text{Adjacent}}{\text{Hypotenuse}} \quad (\text{CAH})\] \[\tan \theta = \frac{\text{Opposite}}{\text{Adjacent}} \quad (\text{TOA})\]
Key Formulas
Worked Examples
- Identify sides relative to \(55^\circ\): \(\text{Opposite} = 75\text{ m}\), \(\text{Hypotenuse} = h\).
- Choose ratio: Sine uses Opp and Hyp (\(\text{SOH}\)).
- Set up equation: \(\sin(55^\circ) = \frac{75}{h}\).
- Rearrange: \(h = \frac{75}{\sin(55^\circ)} = \frac{75}{0.8192} \approx 91.6\text{ m}\).
- Answer: \(91.6\text{ m}\).
- Identify sides: \(\text{Opposite} = 5.4\text{ m}\), \(\text{Hypotenuse} = 27\text{ m}\).
- Choose ratio: \(\sin\theta = \frac{\text{Opp}}{\text{Hyp}} = \frac{5.4}{27} = 0.2\).
- Apply inverse sine: \(\theta = \sin^{-1}(0.2) \approx 11.53^\circ\).
- Answer: \(11.5^\circ\).
- By alternate interior angles, the angle of elevation from the ground target to the drone is also \(40^\circ\).
- Identify sides: \(\text{Opposite} = 80\text{ m}\), \(\text{Adjacent} = d\).
- Choose ratio: \(\tan(40^\circ) = \frac{\text{Opp}}{\text{Adj}} = \frac{80}{d}\).
- Rearrange: \(d = \frac{80}{\tan(40^\circ)} = \frac{80}{0.8391} \approx 95.34\text{ m}\).
- Answer: \(95.3\text{ m}\) (or \(95.4\text{ m}\) using full precision).
Common Mistakes
Real World
Practice