Area
Interactive curriculum lessons, worked examples, and geometric problem-solving techniques designed to help Kenyan students master CBC, KPSEA, KCSE, and IGCSE mathematics.
First Principles
Objective: Find the area of regular and irregular polygons by decomposition.
Concrete Scenario
Imagine a family shamba drawn on paper — its boundary zigzags, so no single textbook formula covers it. However, if you draw straight lines (diagonals) from one corner to the other vertices, the entire plot splits neatly into triangles. Because you already know how to find the area of each triangle, summing them yields the total area of the shamba. This powerful mathematical strategy is called decomposition.
Geometric Insight
Every polygon with \(n\) sides can be partitioned into exactly \(n - 2\) non-overlapping triangles by drawing diagonals from a single chosen vertex. For example, a pentagon (\(5\) sides) splits into \(3\) triangles, while a hexagon (\(6\) sides) splits into \(4\) triangles. The fundamental rule of decomposition is that the sub-shapes must tile the polygon completely without gaps and without overlaps.
Algebraic Rule
If a polygon is decomposed into non-overlapping regions \(T_1, T_2, \dots, T_k\), then:
\[ A_{\text{polygon}} = A_{T_1} + A_{T_2} + \cdots + A_{T_k} \]For each triangle, \(A = \frac{1}{2} b h\), where \(b\) is the base and \(h\) is the perpendicular height. Experiment with the interactive shape splitter below to see live decomposition in action!
🔷 Shape Splitter — Triangulate & Sum Live
Drag any blue vertex to reshape. Red vertex = fan point. Dashed red lines = diagonals.
Key Formulas
Worked Examples
- Identify Dimensions: The rectangle has length \(b = 14\text{ m}\) and width \(h = 8\text{ m}\).
- Calculate Single Triangle Area: \[ A_{T} = \frac{1}{2} \times b \times h = \frac{1}{2} \times 14 \times 8 = 56\text{ m}^2 \]
- Sum the Two Triangles: \[ A_{\text{total}} = 56\text{ m}^2 + 56\text{ m}^2 = 112\text{ m}^2 \]
- Check with Standard Formula: \(A = \ell \times w = 14 \times 8 = 112\text{ m}^2\).
Answer: Total area is \(112\text{ m}^2\) (each triangle is \(56\text{ m}^2\)).
- Identify Sub-regions: The shape consists of \(\text{Rectangle } A\) and \(\text{Rectangle } B\).
- Area of Rectangle A: \[ A_A = 18\text{ m} \times 10\text{ m} = 180\text{ m}^2 \]
- Area of Rectangle B: \[ A_B = 12\text{ m} \times 6\text{ m} = 72\text{ m}^2 \]
- Sum Decomposed Areas: \[ A_{\text{total}} = A_A + A_B = 180 + 72 = 252\text{ m}^2 \]
Answer: \(252\text{ m}^2\)
- Area of Triangle 1: \[ A_{T1} = \frac{1}{2} \times 10 \times 8 = 40\text{ m}^2 \]
- Area of Trapezium: \[ A_{Tr} = \frac{8 + 14}{2} \times 15 = 11 \times 15 = 165\text{ m}^2 \]
- Area of Triangle 2: \[ A_{T2} = \frac{1}{2} \times 12 \times 14 = 84\text{ m}^2 \]
- Sum all Decomposed Parts: \[ A_{\text{total}} = 40 + 165 + 84 = 289\text{ m}^2 \]
Answer: \(289\text{ m}^2\)
Common Mistakes
Real World
Practice