Area of Polygons
Interactive curriculum lessons, worked examples, and geometric problem-solving techniques designed to help Kenyan students master CBC, KPSEA, KCSE, and IGCSE mathematics.
First Principles
Objective: Calculate the area of regular polygons using decomposition into triangles.
Concrete scenario: A hexagonal gazebo floor in a community garden in Nakuru needs tiling. To know how many tiles to buy, you must find the floor area. Instead of measuring the whole hexagon at once, imagine cutting it into triangular slices from the centre — like cutting a round flatbread into equal slices. Each slice is an isosceles triangle, and you already know how to find the area of a triangle.
Geometric insight: Every regular polygon can be split into \(n\) identical isosceles triangles, where \(n\) is the number of sides. Each triangle has its base along one side of the polygon and its apex at the centre. The perpendicular distance from the centre to a side is called the apothem (\(a\)) — it acts as the exact height of every triangular slice.
Algebraic rule: If each triangle has base \(s\) (side length) and height \(a\) (apothem), then one triangle's area is \(\frac{1}{2} s a\). With \(n\) identical triangles, the total area is: \[A = n \times \left(\frac{1}{2} s a\right) = \frac{1}{2} (n s) a = \frac{1}{2} P a\] where \(P = n \times s\) is the perimeter of the regular polygon.
Perimeter (\(P\)): —
One slice area: —
Total polygon area: —
Key Formulas
Worked Examples
A regular pentagon has a side length \(s = 6\text{ cm}\) and an apothem \(a = 4.13\text{ cm}\). Find its total area.
- Identify given values: Number of sides \(n = 5\), side length \(s = 6\text{ cm}\), apothem \(a = 4.13\text{ cm}\).
- Calculate perimeter (\(P\)): \[P = n \times s = 5 \times 6 = 30\text{ cm}\]
- Apply polygon area formula: \[A = \frac{1}{2} \times P \times a = \frac{1}{2} \times 30 \times 4.13\]
- Compute result: \[A = 15 \times 4.13 = 61.95\text{ cm}^2\]
A decorative regular hexagonal paving stone has a side length \(s = 8\text{ cm}\) and an apothem \(a = 6.93\text{ cm}\). Find its area by calculating the area of one triangular slice first.
- Identify slice dimensions: The base of one triangular slice is \(s = 8\text{ cm}\) and the perpendicular height is \(a = 6.93\text{ cm}\).
- Calculate area of one slice: \[A_{\text{slice}} = \frac{1}{2} \times \text{base} \times \text{height} = \frac{1}{2} \times 8 \times 6.93 = 27.72\text{ cm}^2\]
- Multiply by the total number of slices: A regular hexagon splits into \(n = 6\) equal triangles. \[A_{\text{total}} = 6 \times A_{\text{slice}} = 6 \times 27.72 = 166.32\text{ cm}^2\]
A school gazebo in Nairobi is built as a regular octagon with side length \(s = 2.5\text{ m}\) and apothem \(a = 3.04\text{ m}\). Find the floor area, and determine how many square tiles measuring \(0.5\text{ m} \times 0.5\text{ m}\) (each \(0.25\text{ m}^2\)) are required to cover the entire floor.
- Determine perimeter: \[P = 8 \times 2.5 = 20\text{ m}\]
- Compute total floor area: \[A = \frac{1}{2} \times P \times a = \frac{1}{2} \times 20 \times 3.04 = 10 \times 3.04 = 30.4\text{ m}^2\]
- Determine number of tiles: \[\text{Tiles required} = \frac{\text{Total Area}}{\text{Tile Area}} = \frac{30.4}{0.25} = 121.6\]
- Practical rounding: Since partial tiles cannot be purchased, round up to \(122\) tiles.
Common Mistakes
Real World
Practice