Reflection
Interactive curriculum lessons, worked examples, and geometric problem-solving techniques designed to help Kenyan students master CBC, KPSEA, KCSE, and IGCSE mathematics.
First Principles
Core Concept: A reflection is an isometric transformation that flips a shape across a fixed line called the mirror line (or axis of reflection).
Pan-African Context: Look closely at a hand-woven Kenyan kiondo or a traditional Ghanaian Kente cloth strip. Many iconic motifs are created by reflecting geometric shapes across a central seam. Every decorative diamond or zig-zag on the left is mirrored on the right at the exact same distance from the centerline.
1. The Geometry of a Reflection
For any point \(P\) and its reflected image \(P'\):
- The mirror line is the perpendicular bisector of the segment \(PP'\).
- The perpendicular distance from \(P\) to the mirror line equals the perpendicular distance from \(P'\) to the mirror line: \(\text{dist}(P, \text{line}) = \text{dist}(P', \text{line})\).
- Points lying directly on the mirror line are invariant (they do not move: \(P = P'\)).
- Reflection reverses the orientation (lateral inversion or handedness) while preserving all side lengths, perimeters, and angles (congruence).
Interactive Reflection Laboratory
Drag the blue vertices to modify the original triangle. Rotate the slider to see how the red image reflects across the line.
Key Formulas
Standard Coordinate Reflection Rules
1. Reflection across the \(y\)-axis (Line \(x = 0\)):
\[(x, y) \to (-x, y)\]The \(x\)-coordinate is negated; the \(y\)-coordinate is unchanged.
2. Reflection across the \(x\)-axis (Line \(y = 0\)):
\[(x, y) \to (x, -y)\]The \(y\)-coordinate is negated; the \(x\)-coordinate is unchanged.
3. Reflection across vertical line \(x = k\):
\[(x, y) \to (2k - x, y)\]The midpoint of the \(x\)-coordinates is \(k\), so \(\frac{x + x'}{2} = k \implies x' = 2k - x\).
4. Reflection across horizontal line \(y = k\):
\[(x, y) \to (x, 2k - y)\]The midpoint of the \(y\)-coordinates is \(k\), so \(\frac{y + y'}{2} = k \implies y' = 2k - y\).
5. Reflection across diagonal line \(y = x\):
\[(x, y) \to (y, x)\]Swap the coordinates.
6. Reflection across diagonal line \(y = -x\):
\[(x, y) \to (-y, -x)\]Swap and negate both coordinates.
Worked Examples
Example 1 (Easy): Reflection in a Standard Axis
A surveyor in Machakos plots a landmark at \(P(-7, 4)\). Find the coordinates of the image point \(P'\) after reflection in the \(y\)-axis.
- Identify the transformation rule: For reflection in the \(y\)-axis (the line \(x = 0\)), the mapping rule is \((x, y) \to (-x, y)\).
- Apply the coordinates: \[x' = -(-7) = 7\] \[y' = 4\]
- Conclusion: The reflected point is \(P'(7, 4)\).
Example 2 (Medium): Reflection Across a Vertical Line \(x = k\)
Point \(A(2, -3)\) is reflected in the line \(x = 5\) to give \(A'\). Find the coordinates of \(A'\) and the distance between \(A\) and \(A'\).
- Identify the formula: For reflection in the vertical line \(x = k\), \(x' = 2k - x\) and \(y' = y\). Here, \(k = 5\).
- Compute the new coordinates: \[x' = 2(5) - 2 = 10 - 2 = 8\] \[y' = -3\] Thus, \(A' = (8, -3)\).
- Calculate the distance: Since both points share the same \(y\)-value, the distance is purely horizontal: \[\text{Distance} = |x' - x| = |8 - 2| = 6\text{ units}\] Check: The distance from \(A\) to \(x=5\) is \(|5 - 2| = 3\). The total distance is \(2 \times 3 = 6\).
Example 3 (Hard): Composite Transformation and Invariance
A solar panel array has a vertex at \(Q(3, -2)\). It is first reflected across the line \(y = x\) to produce \(Q_1\), and then \(Q_1\) is reflected across the horizontal line \(y = 2\) to produce \(Q_2\). Determine the final coordinates of \(Q_2\).
- Step 1 (Reflection in \(y = x\)): Applying \((x, y) \to (y, x)\): \[Q_1 = (-2, 3)\]
- Step 2 (Reflection in \(y = 2\)): For reflection in \(y = k\) with \(k = 2\), \(x_2 = x_1\) and \(y_2 = 2k - y_1\): \[x_2 = -2\] \[y_2 = 2(2) - 3 = 4 - 3 = 1\]
- Conclusion: The final position is \(Q_2(-2, 1)\).
Common Mistakes
The Error: Thinking that reflecting in the \(x\)-axis changes the \(x\)-coordinate.
Why it feels right: The word "\(x\)-axis" makes students naturally want to change \(x\).
The Correction: Crossing over the horizontal \(x\)-axis moves a point up or down, changing only its vertical coordinate (\(y\) becomes \(-y\)). Likewise, reflecting across the vertical \(y\)-axis moves left/right, changing \(x\) to \(-x\).
The Error: Drawing the reflected triangle on the other side of the mirror line facing the same direction as the original.
Why it feels right: The distances from the axis look equal, and the shape is congruent.
The Correction: Reflection creates a lateral inversion. If a triangle points toward the mirror line on the left, its image must point toward the mirror line from the right.
The Error: Writing \(x' = k - x\) instead of \(x' = 2k - x\).
Why it feels right: \(k - x\) represents the distance from the point to the mirror line, not the new position.
The Correction: The new position must add that same distance past the mirror line: \(k + (k - x) = 2k - x\).
Real World
Practice