Vectors (Basic)
Interactive curriculum lessons, worked examples, and geometric problem-solving techniques designed to help Kenyan students master CBC, KPSEA, KCSE, and IGCSE mathematics.
First Principles
Objective
Perform basic vector addition, subtraction, scalar multiplication, and calculate vector magnitude.
Concrete Scenario: A medical drone leaves a depot on the shore of Lake Victoria. The pilot commands it to fly 3 units East and 1 unit North \(\mathbf{a} = \begin{pmatrix} 3 \\ 1 \end{pmatrix}\). A crosswind pushes the drone 1 unit East and 2 units South \(\mathbf{b} = \begin{pmatrix} 1 \\ -2 \end{pmatrix}\). Where does the drone actually land? To find out, we add the two displacement vectors.
Geometric & Algebraic Insight:
- Tip-to-Tail Rule: Draw vector \(\mathbf{a}\). From the tip (end) of \(\mathbf{a}\), draw vector \(\mathbf{b}\). The vector from the start of \(\mathbf{a}\) to the tip of \(\mathbf{b}\) is the resultant vector \(\mathbf{a} + \mathbf{b}\).
- Column Vectors: Adding vectors means adding horizontal steps together and vertical steps together: \(\begin{pmatrix} a_x \\ a_y \end{pmatrix} + \begin{pmatrix} b_x \\ b_y \end{pmatrix} = \begin{pmatrix} a_x + b_x \\ a_y + b_y \end{pmatrix}\).
- Vector Magnitude: The length of vector \(\mathbf{v} = \begin{pmatrix} v_x \\ v_y \end{pmatrix}\) is found using Pythagoras: \(|\mathbf{v}| = \sqrt{v_x^2 + v_y^2}\).
Vector Addition (Tip-to-Tail Method)
Key Formulas
Worked Examples
Problem: Given \(\mathbf{a} = \begin{pmatrix} 3 \\ 1 \end{pmatrix}\) and \(\mathbf{b} = \begin{pmatrix} 1 \\ 4 \end{pmatrix}\), find \(\mathbf{a} + \mathbf{b}\) and its magnitude.
- Add components: \[\mathbf{a} + \mathbf{b} = \begin{pmatrix} 3 + 1 \\ 1 + 4 \end{pmatrix} = \begin{pmatrix} 4 \\ 5 \end{pmatrix}\]
- Calculate magnitude: \[|\mathbf{a} + \mathbf{b}| = \sqrt{4^2 + 5^2} = \sqrt{16 + 25} = \sqrt{41} \approx 6.40\]
Problem: Given \(\mathbf{u} = 2\mathbf{i} + 5\mathbf{j}\) and \(\mathbf{v} = -\mathbf{i} + 3\mathbf{j}\), calculate \(2\mathbf{u} - \mathbf{v}\).
- Scale vector \(\mathbf{u}\): \[2\mathbf{u} = 2(2\mathbf{i} + 5\mathbf{j}) = 4\mathbf{i} + 10\mathbf{j}\]
- Subtract \(\mathbf{v}\): \[2\mathbf{u} - \mathbf{v} = (4 - (-1))\mathbf{i} + (10 - 3)\mathbf{j} = 5\mathbf{i} + 7\mathbf{j}\]
Problem: Vector \(\mathbf{A} = 3\mathbf{i} - 2\mathbf{j}\). Vector \(\mathbf{B}\) has magnitude 5 at an angle of 60° to the positive x-axis. Find the x-component of \(\mathbf{A} + \mathbf{B}\).
- Find x-component of vector \(\mathbf{B}\): \[B_x = 5 \cos(60^{\circ}) = 5(0.5) = 2.5\]
- Add x-components: \(A_x + B_x = 3 + 2.5 = 5.5\).
Common Mistakes
Real World
Practice